13040104100333 has 2 divisors, whose sum is σ = 13040104100334. Its totient is φ = 13040104100332.

The previous prime is 13040104100327. The next prime is 13040104100347. The reversal of 13040104100333 is 33300140104031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11308874459689 + 1731229640644 = 3362867^2 + 1315762^2 .

It is an emirp because it is prime and its reverse (33300140104031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13040104100333 - 2⁸ = 13040104100077 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13040104100299 and 13040104100308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13040104100633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520052050166 + 6520052050167.

It is an arithmetic number, because the mean of its divisors is an integer number (6520052050167).

Almost surely, 2^{13040104100333} is an apocalyptic number.

It is an amenable number.

13040104100333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13040104100333 is an equidigital number, since it uses as much as digits as its factorization.

13040104100333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13040104100333 its reverse (33300140104031), we get a palindrome (46340244204364).

The spelling of 13040104100333 in words is "thirteen trillion, forty billion, one hundred four million, one hundred thousand, three hundred thirty-three".