Base | Representation |
---|---|
bin | 111100101110010000… |
… | …0110110011111010111 |
3 | 110110120212201222210001 |
4 | 1321130200312133113 |
5 | 4114030142301201 |
6 | 135523324512131 |
7 | 12264314232562 |
oct | 1713440663727 |
9 | 413525658701 |
10 | 130401134551 |
11 | 5033704a496 |
12 | 213330ab647 |
13 | c3b202265c |
14 | 64508874d9 |
15 | 35d319d301 |
hex | 1e5c8367d7 |
130401134551 has 2 divisors, whose sum is σ = 130401134552. Its totient is φ = 130401134550.
The previous prime is 130401134471. The next prime is 130401134561. The reversal of 130401134551 is 155431104031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130401134551 - 211 = 130401132503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130401134561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65200567275 + 65200567276.
It is an arithmetic number, because the mean of its divisors is an integer number (65200567276).
Almost surely, 2130401134551 is an apocalyptic number.
130401134551 is a deficient number, since it is larger than the sum of its proper divisors (1).
130401134551 is an equidigital number, since it uses as much as digits as its factorization.
130401134551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 130401134551 its reverse (155431104031), we get a palindrome (285832238582).
The spelling of 130401134551 in words is "one hundred thirty billion, four hundred one million, one hundred thirty-four thousand, five hundred fifty-one".
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