130401730117 has 2 divisors, whose sum is σ = 130401730118. Its totient is φ = 130401730116.

The previous prime is 130401730087. The next prime is 130401730127. The reversal of 130401730117 is 711037104031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110224664001 + 20177066116 = 332001^2 + 142046^2 .

It is a cyclic number.

It is not a de Polignac number, because 130401730117 - 2¹¹ = 130401728069 is a prime.

It is a super-2 number, since 2×130401730117² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130401730127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65200865058 + 65200865059.

It is an arithmetic number, because the mean of its divisors is an integer number (65200865059).

Almost surely, 2^130401730117 is an apocalyptic number.

It is an amenable number.

130401730117 is a deficient number, since it is larger than the sum of its proper divisors (1).

130401730117 is an equidigital number, since it uses as much as digits as its factorization.

130401730117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1764, while the sum is 28.

Adding to 130401730117 its reverse (711037104031), we get a palindrome (841438834148).

The spelling of 130401730117 in words is "one hundred thirty billion, four hundred one million, seven hundred thirty thousand, one hundred seventeen".