Base | Representation |
---|---|
bin | 1011110111000010100100… |
… | …0010000001011110111111 |
3 | 1201011122001121000210111012 |
4 | 2331300221002001132333 |
5 | 3202122322012410004 |
6 | 43422331145145435 |
7 | 2514060352356263 |
oct | 275605102013677 |
9 | 51148047023435 |
10 | 13040209106879 |
11 | 417835a0a0939 |
12 | 156734378b27b |
13 | 7378c0163156 |
14 | 3312142a60a3 |
15 | 1793146c646e |
hex | bdc290817bf |
13040209106879 has 2 divisors, whose sum is σ = 13040209106880. Its totient is φ = 13040209106878.
The previous prime is 13040209106867. The next prime is 13040209106983. The reversal of 13040209106879 is 97860190204031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13040209106879 - 220 = 13040208058303 is a prime.
It is a super-2 number, since 2×130402091068792 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13040209106809) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520104553439 + 6520104553440.
It is an arithmetic number, because the mean of its divisors is an integer number (6520104553440).
Almost surely, 213040209106879 is an apocalyptic number.
13040209106879 is a deficient number, since it is larger than the sum of its proper divisors (1).
13040209106879 is an equidigital number, since it uses as much as digits as its factorization.
13040209106879 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 653184, while the sum is 50.
The spelling of 13040209106879 in words is "thirteen trillion, forty billion, two hundred nine million, one hundred six thousand, eight hundred seventy-nine".
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