Base | Representation |
---|---|
bin | 11101101001100111010111… |
… | …001010111011011010110001 |
3 | 122002201102020002102200020120 |
4 | 131221213113022323122301 |
5 | 114043011033140240423 |
6 | 1141202210200000453 |
7 | 36316212452414643 |
oct | 3551472712733261 |
9 | 562642202380216 |
10 | 130403112040113 |
11 | 38606716165400 |
12 | 12760bb6460129 |
13 | 579bc64875883 |
14 | 242b7897b0893 |
15 | 101213e2b7ee3 |
hex | 7699d72bb6b1 |
130403112040113 has 48 divisors (see below), whose sum is σ = 191666121333120. Its totient is φ = 78803997226240.
The previous prime is 130403112040079. The next prime is 130403112040153. The reversal of 130403112040113 is 311040211304031.
It is a happy number.
It is not a de Polignac number, because 130403112040113 - 29 = 130403112039601 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130403112040153) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1429922845 + ... + 1430014037.
It is an arithmetic number, because the mean of its divisors is an integer number (3993044194440).
Almost surely, 2130403112040113 is an apocalyptic number.
It is an amenable number.
130403112040113 is a deficient number, since it is larger than the sum of its proper divisors (61263009293007).
130403112040113 is a wasteful number, since it uses less digits than its factorization.
130403112040113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102550 (or 102539 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 130403112040113 its reverse (311040211304031), we get a palindrome (441443323344144).
The spelling of 130403112040113 in words is "one hundred thirty trillion, four hundred three billion, one hundred twelve million, forty thousand, one hundred thirteen".
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