Base | Representation |
---|---|
bin | 1011110111000011000001… |
… | …0000000111011111010011 |
3 | 1201011122101000222002122021 |
4 | 2331300300100013133103 |
5 | 3202123044020221003 |
6 | 43422351153352311 |
7 | 2514063353116021 |
oct | 275606020073723 |
9 | 51148330862567 |
10 | 13040330242003 |
11 | 4178411508509 |
12 | 1567378268697 |
13 | 73790c29693c |
14 | 3312263d9711 |
15 | 1793201532bd |
hex | bdc304077d3 |
13040330242003 has 2 divisors, whose sum is σ = 13040330242004. Its totient is φ = 13040330242002.
The previous prime is 13040330241979. The next prime is 13040330242007. The reversal of 13040330242003 is 30024203304031.
13040330242003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13040330242003 - 25 = 13040330241971 is a prime.
It is not a weakly prime, because it can be changed into another prime (13040330242007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520165121001 + 6520165121002.
It is an arithmetic number, because the mean of its divisors is an integer number (6520165121002).
Almost surely, 213040330242003 is an apocalyptic number.
13040330242003 is a deficient number, since it is larger than the sum of its proper divisors (1).
13040330242003 is an equidigital number, since it uses as much as digits as its factorization.
13040330242003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 13040330242003 its reverse (30024203304031), we get a palindrome (43064533546034).
The spelling of 13040330242003 in words is "thirteen trillion, forty billion, three hundred thirty million, two hundred forty-two thousand, three".
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