13040375557073 has 2 divisors, whose sum is σ = 13040375557074. Its totient is φ = 13040375557072.

The previous prime is 13040375557003. The next prime is 13040375557123. The reversal of 13040375557073 is 37075557304031.

It is an a-pointer prime, because the next prime (13040375557123) can be obtained adding 13040375557073 to its sum of digits (50).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11843075656129 + 1197299900944 = 3441377^2 + 1094212^2 .

It is a cyclic number.

It is not a de Polignac number, because 13040375557073 - 2³⁴ = 13023195687889 is a prime.

It is not a weakly prime, because it can be changed into another prime (13040375557003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520187778536 + 6520187778537.

It is an arithmetic number, because the mean of its divisors is an integer number (6520187778537).

Almost surely, 2^{13040375557073} is an apocalyptic number.

It is an amenable number.

13040375557073 is a deficient number, since it is larger than the sum of its proper divisors (1).

13040375557073 is an equidigital number, since it uses as much as digits as its factorization.

13040375557073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4630500, while the sum is 50.

The spelling of 13040375557073 in words is "thirteen trillion, forty billion, three hundred seventy-five million, five hundred fifty-seven thousand, seventy-three".