Base | Representation |
---|---|
bin | 111100101110010110… |
… | …0010111001100111101 |
3 | 110110121002102022010001 |
4 | 1321130230113030331 |
5 | 4114031430332000 |
6 | 135523513314301 |
7 | 12264352001302 |
oct | 1713454271475 |
9 | 413532368101 |
10 | 130404152125 |
11 | 50338820655 |
12 | 21334105991 |
13 | c3b283acc0 |
14 | 64510310a9 |
15 | 35d359746a |
hex | 1e5cb1733d |
130404152125 has 32 divisors (see below), whose sum is σ = 176542775136. Its totient is φ = 95595379200.
The previous prime is 130404152111. The next prime is 130404152161. The reversal of 130404152125 is 521251404031.
It can be written as a sum of positive squares in 16 ways, for example, as 90214327449 + 40189824676 = 300357^2 + 200474^2 .
It is not a de Polignac number, because 130404152125 - 211 = 130404150077 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130404152093 and 130404152102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 70254 + ... + 515503.
It is an arithmetic number, because the mean of its divisors is an integer number (5516961723).
Almost surely, 2130404152125 is an apocalyptic number.
It is an amenable number.
130404152125 is a deficient number, since it is larger than the sum of its proper divisors (46138623011).
130404152125 is a wasteful number, since it uses less digits than its factorization.
130404152125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 585922 (or 585912 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 130404152125 its reverse (521251404031), we get a palindrome (651655556156).
The spelling of 130404152125 in words is "one hundred thirty billion, four hundred four million, one hundred fifty-two thousand, one hundred twenty-five".
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