Base | Representation |
---|---|
bin | 10010111110011110111… |
… | …011110001110101010000 |
3 | 11121122221220021001020022 |
4 | 102332132323301311100 |
5 | 132331134114431144 |
6 | 2435022440203012 |
7 | 163133236245320 |
oct | 22763673616520 |
9 | 4548856231208 |
10 | 1304041561424 |
11 | 46304a5130a8 |
12 | 190894a69468 |
13 | 95c8050b2c4 |
14 | 4718a23b280 |
15 | 23dc3b59cee |
hex | 12f9eef1d50 |
1304041561424 has 40 divisors (see below), whose sum is σ = 2887718203968. Its totient is φ = 558836709120.
The previous prime is 1304041561411. The next prime is 1304041561441. The reversal of 1304041561424 is 4241651404031.
It is a super-2 number, since 2×13040415614242 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1276844 + ... + 2058740.
Almost surely, 21304041561424 is an apocalyptic number.
1304041561424 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
1304041561424 is an abundant number, since it is smaller than the sum of its proper divisors (1583676642544).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1304041561424 is a wasteful number, since it uses less digits than its factorization.
1304041561424 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 796803 (or 796797 counting only the distinct ones).
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 1304041561424 its reverse (4241651404031), we get a palindrome (5545692965455).
The spelling of 1304041561424 in words is "one trillion, three hundred four billion, forty-one million, five hundred sixty-one thousand, four hundred twenty-four".
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