Base | Representation |
---|---|
bin | 10010111110011111000… |
… | …010001100011011010101 |
3 | 11121122222000102111020002 |
4 | 102332133002030123111 |
5 | 132331140032240341 |
6 | 2435022540221045 |
7 | 163133256451445 |
oct | 22763702143325 |
9 | 4548860374202 |
10 | 1304043243221 |
11 | 463050461714 |
12 | 19089553a785 |
13 | 95c80979954 |
14 | 4718a558125 |
15 | 23dc3d8d29b |
hex | 12f9f08c6d5 |
1304043243221 has 2 divisors, whose sum is σ = 1304043243222. Its totient is φ = 1304043243220.
The previous prime is 1304043243179. The next prime is 1304043243227. The reversal of 1304043243221 is 1223423404031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1010155654225 + 293887588996 = 1005065^2 + 542114^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1304043243221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304043243227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652021621610 + 652021621611.
It is an arithmetic number, because the mean of its divisors is an integer number (652021621611).
Almost surely, 21304043243221 is an apocalyptic number.
It is an amenable number.
1304043243221 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304043243221 is an equidigital number, since it uses as much as digits as its factorization.
1304043243221 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 1304043243221 its reverse (1223423404031), we get a palindrome (2527466647252).
The spelling of 1304043243221 in words is "one trillion, three hundred four billion, forty-three million, two hundred forty-three thousand, two hundred twenty-one".
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