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13040440116997 is a prime number
BaseRepresentation
bin1011110111000011011011…
…0011010000011100000101
31201011122122200201022210111
42331300312303100130011
53202123310132220442
643422410120353021
72514066156050206
oct275606663203405
951148580638714
1013040440116997
114178468534197
1215673a9015771
13737928c87127
14331236c3b5ad
15179329b08b17
hexbdc36cd0705

13040440116997 has 2 divisors, whose sum is σ = 13040440116998. Its totient is φ = 13040440116996.

The previous prime is 13040440116983. The next prime is 13040440117031. The reversal of 13040440116997 is 79961104404031.

13040440116997 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12605155539876 + 435284577121 = 3550374^2 + 659761^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13040440116997 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13040440116997.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13040440117997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520220058498 + 6520220058499.

It is an arithmetic number, because the mean of its divisors is an integer number (6520220058499).

Almost surely, 213040440116997 is an apocalyptic number.

It is an amenable number.

13040440116997 is a deficient number, since it is larger than the sum of its proper divisors (1).

13040440116997 is an equidigital number, since it uses as much as digits as its factorization.

13040440116997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 653184, while the sum is 49.

The spelling of 13040440116997 in words is "thirteen trillion, forty billion, four hundred forty million, one hundred sixteen thousand, nine hundred ninety-seven".