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1304044520050 = 25226080890401
BaseRepresentation
bin10010111110011111000…
…111000100001001110010
311121122222002211100201001
4102332133013010021302
5132331140344120200
62435023023432214
7163133303350126
oct22763707041162
94548862740631
101304044520050
11463051153a48
12190895a5566a
1395c81005b7c
144718a7ab586
1523dc404176a
hex12f9f1c4272

1304044520050 has 12 divisors (see below), whose sum is σ = 2425522807386. Its totient is φ = 521617808000.

The previous prime is 1304044520047. The next prime is 1304044520069. The reversal of 1304044520050 is 500254404031.

It can be written as a sum of positive squares in 3 ways, for example, as 1219683898449 + 84360621601 = 1104393^2 + 290449^2 .

It is a super-2 number, since 2×13040445200502 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 13040445151 + ... + 13040445250.

Almost surely, 21304044520050 is an apocalyptic number.

1304044520050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1304044520050 is a deficient number, since it is larger than the sum of its proper divisors (1121478287336).

1304044520050 is a wasteful number, since it uses less digits than its factorization.

1304044520050 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26080890413 (or 26080890408 counting only the distinct ones).

The product of its (nonzero) digits is 9600, while the sum is 28.

Adding to 1304044520050 its reverse (500254404031), we get a palindrome (1804298924081).

The spelling of 1304044520050 in words is "one trillion, three hundred four billion, forty-four million, five hundred twenty thousand, fifty".

Divisors: 1 2 5 10 25 50 26080890401 52161780802 130404452005 260808904010 652022260025 1304044520050