Base | Representation |
---|---|
bin | 1011110111000011111000… |
… | …0001011011001000001000 |
3 | 1201011122222010200121021001 |
4 | 2331300332001123020020 |
5 | 3202124032141140204 |
6 | 43422430125224344 |
7 | 2514102156616600 |
oct | 275607601331010 |
9 | 51148863617231 |
10 | 13040561271304 |
11 | 417851a964216 |
12 | 15674217020b4 |
13 | 7379480c6578 |
14 | 331248d77c00 |
15 | 17933558b4a4 |
hex | bdc3e05b208 |
13040561271304 has 48 divisors (see below), whose sum is σ = 28561082142780. Its totient is φ = 5565621841920.
The previous prime is 13040561271289. The next prime is 13040561271329. The reversal of 13040561271304 is 40317216504031.
It is a happy number.
It can be written as a sum of positive squares in 2 ways, for example, as 12491969222404 + 548592048900 = 3534398^2 + 740670^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 68923657 + ... + 69112600.
Almost surely, 213040561271304 is an apocalyptic number.
13040561271304 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13040561271304 is an abundant number, since it is smaller than the sum of its proper divisors (15520520871476).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13040561271304 is a wasteful number, since it uses less digits than its factorization.
13040561271304 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 138036518 (or 138036507 counting only the distinct ones).
The product of its (nonzero) digits is 60480, while the sum is 37.
Adding to 13040561271304 its reverse (40317216504031), we get a palindrome (53357777775335).
The spelling of 13040561271304 in words is "thirteen trillion, forty billion, five hundred sixty-one million, two hundred seventy-one thousand, three hundred four".
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