Base | Representation |
---|---|
bin | 11101101001101110000100… |
… | …111111110010001001110011 |
3 | 122002202002211122201201112212 |
4 | 131221232010333302021303 |
5 | 114043120320232241314 |
6 | 1141205401522442335 |
7 | 36316556245325546 |
oct | 3551560477621163 |
9 | 562662748651485 |
10 | 130410323321459 |
11 | 386097867a7855 |
12 | 127624895033ab |
13 | 579c84388595c |
14 | 242bc7140885d |
15 | 1012412418e3e |
hex | 769b84ff2273 |
130410323321459 has 2 divisors, whose sum is σ = 130410323321460. Its totient is φ = 130410323321458.
The previous prime is 130410323321329. The next prime is 130410323321461. The reversal of 130410323321459 is 954123323014031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130410323321459 - 216 = 130410323255923 is a prime.
Together with 130410323321461, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (130410328321459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205161660729 + 65205161660730.
It is an arithmetic number, because the mean of its divisors is an integer number (65205161660730).
Almost surely, 2130410323321459 is an apocalyptic number.
130410323321459 is a deficient number, since it is larger than the sum of its proper divisors (1).
130410323321459 is an equidigital number, since it uses as much as digits as its factorization.
130410323321459 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 233280, while the sum is 41.
The spelling of 130410323321459 in words is "one hundred thirty trillion, four hundred ten billion, three hundred twenty-three million, three hundred twenty-one thousand, four hundred fifty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •