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130410323321459 is a prime number
BaseRepresentation
bin11101101001101110000100…
…111111110010001001110011
3122002202002211122201201112212
4131221232010333302021303
5114043120320232241314
61141205401522442335
736316556245325546
oct3551560477621163
9562662748651485
10130410323321459
11386097867a7855
12127624895033ab
13579c84388595c
14242bc7140885d
151012412418e3e
hex769b84ff2273

130410323321459 has 2 divisors, whose sum is σ = 130410323321460. Its totient is φ = 130410323321458.

The previous prime is 130410323321329. The next prime is 130410323321461. The reversal of 130410323321459 is 954123323014031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130410323321459 - 216 = 130410323255923 is a prime.

Together with 130410323321461, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130410328321459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205161660729 + 65205161660730.

It is an arithmetic number, because the mean of its divisors is an integer number (65205161660730).

Almost surely, 2130410323321459 is an apocalyptic number.

130410323321459 is a deficient number, since it is larger than the sum of its proper divisors (1).

130410323321459 is an equidigital number, since it uses as much as digits as its factorization.

130410323321459 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 233280, while the sum is 41.

The spelling of 130410323321459 in words is "one hundred thirty trillion, four hundred ten billion, three hundred twenty-three million, three hundred twenty-one thousand, four hundred fifty-nine".