Base | Representation |
---|---|
bin | 111100101110100001… |
… | …1111001111000101101 |
3 | 110110121112000211122112 |
4 | 1321131003321320231 |
5 | 4114040020323001 |
6 | 135524253453405 |
7 | 12264455313533 |
oct | 1713503717055 |
9 | 413545024575 |
10 | 130410323501 |
11 | 50341256267 |
12 | 213361a1265 |
13 | c3b3bbbcc3 |
14 | 6451b9a153 |
15 | 35d3db5cbb |
hex | 1e5d0f9e2d |
130410323501 has 2 divisors, whose sum is σ = 130410323502. Its totient is φ = 130410323500.
The previous prime is 130410323443. The next prime is 130410323599. The reversal of 130410323501 is 105323014031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 75349701001 + 55060622500 = 274499^2 + 234650^2 .
It is an emirp because it is prime and its reverse (105323014031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130410323501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130410323101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205161750 + 65205161751.
It is an arithmetic number, because the mean of its divisors is an integer number (65205161751).
Almost surely, 2130410323501 is an apocalyptic number.
It is an amenable number.
130410323501 is a deficient number, since it is larger than the sum of its proper divisors (1).
130410323501 is an equidigital number, since it uses as much as digits as its factorization.
130410323501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 130410323501 its reverse (105323014031), we get a palindrome (235733337532).
The spelling of 130410323501 in words is "one hundred thirty billion, four hundred ten million, three hundred twenty-three thousand, five hundred one".
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