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13041121 is a prime number
BaseRepresentation
bin110001101111…
…110111100001
3220112120001111
4301233313201
511314303441
61143303321
7215563522
oct61576741
926476044
1013041121
1173a7a95
12444ab41
132917b52
141a36849
151229081
hexc6fde1

13041121 has 2 divisors, whose sum is σ = 13041122. Its totient is φ = 13041120.

The previous prime is 13041113. The next prime is 13041143. The reversal of 13041121 is 12114031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10595025 + 2446096 = 3255^2 + 1564^2 .

It is a cyclic number.

It is not a de Polignac number, because 13041121 - 23 = 13041113 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13041101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520560 + 6520561.

It is an arithmetic number, because the mean of its divisors is an integer number (6520561).

Almost surely, 213041121 is an apocalyptic number.

It is an amenable number.

13041121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13041121 is an equidigital number, since it uses as much as digits as its factorization.

13041121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 13041121 is about 3611.2492298372. The cubic root of 13041121 is about 235.3811289383.

Adding to 13041121 its reverse (12114031), we get a palindrome (25155152).

The spelling of 13041121 in words is "thirteen million, forty-one thousand, one hundred twenty-one".