130411241101032 has 64 divisors (see below), whose sum is σ = 326395310707200. Its totient is φ = 43421458129920.

The previous prime is 130411241101007. The next prime is 130411241101033. The reversal of 130411241101032 is 230101142114031.

It is a super-2 number, since 2×130411241101032² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a junction number, because it is equal to n+sod(n) for n = 130411241100993 and 130411241101011.

It is not an unprimeable number, because it can be changed into a prime (130411241101033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 401945769 + ... + 402270087.

It is an arithmetic number, because the mean of its divisors is an integer number (5099926729800).

Almost surely, 2^{130411241101032} is an apocalyptic number.

130411241101032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

130411241101032 is an abundant number, since it is smaller than the sum of its proper divisors (195984069606168).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130411241101032 is a wasteful number, since it uses less digits than its factorization.

130411241101032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 343146 (or 343142 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 130411241101032 its reverse (230101142114031), we get a palindrome (360512383215063).

The spelling of 130411241101032 in words is "one hundred thirty trillion, four hundred eleven billion, two hundred forty-one million, one hundred one thousand, thirty-two".