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130411421233 is a prime number
BaseRepresentation
bin111100101110100100…
…0000101111000110001
3110110121121002121110021
41321131020011320301
54114040310434413
6135524333203441
712264500535112
oct1713510057061
9413547077407
10130411421233
1150341935a85
1221336630581
13c3b41b4852
146451da4209
1535d403118d
hex1e5d205e31

130411421233 has 2 divisors, whose sum is σ = 130411421234. Its totient is φ = 130411421232.

The previous prime is 130411421219. The next prime is 130411421267. The reversal of 130411421233 is 332124114031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109238843169 + 21172578064 = 330513^2 + 145508^2 .

It is a cyclic number.

It is not a de Polignac number, because 130411421233 - 29 = 130411420721 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130411421198 and 130411421207.

It is not a weakly prime, because it can be changed into another prime (130411431233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205710616 + 65205710617.

It is an arithmetic number, because the mean of its divisors is an integer number (65205710617).

Almost surely, 2130411421233 is an apocalyptic number.

It is an amenable number.

130411421233 is a deficient number, since it is larger than the sum of its proper divisors (1).

130411421233 is an equidigital number, since it uses as much as digits as its factorization.

130411421233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 130411421233 its reverse (332124114031), we get a palindrome (462535535264).

The spelling of 130411421233 in words is "one hundred thirty billion, four hundred eleven million, four hundred twenty-one thousand, two hundred thirty-three".