Base | Representation |
---|---|
bin | 10010111110100011011… |
… | …011100110010110110001 |
3 | 11121200011011020022210222 |
4 | 102332203123212112301 |
5 | 132331312423340024 |
6 | 2435034133302425 |
7 | 163135143462446 |
oct | 22764333462661 |
9 | 4550134208728 |
10 | 1304117011889 |
11 | 46308906715a |
12 | 1908b6194a15 |
13 | 95c93037953 |
14 | 4719627b9cd |
15 | 23dca5b085e |
hex | 12fa36e65b1 |
1304117011889 has 2 divisors, whose sum is σ = 1304117011890. Its totient is φ = 1304117011888.
The previous prime is 1304117011867. The next prime is 1304117011891. The reversal of 1304117011889 is 9881107114031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1291529967025 + 12587044864 = 1136455^2 + 112192^2 .
It is a cyclic number.
It is not a de Polignac number, because 1304117011889 - 220 = 1304115963313 is a prime.
Together with 1304117011891, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1304117011489) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652058505944 + 652058505945.
It is an arithmetic number, because the mean of its divisors is an integer number (652058505945).
Almost surely, 21304117011889 is an apocalyptic number.
It is an amenable number.
1304117011889 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304117011889 is an equidigital number, since it uses as much as digits as its factorization.
1304117011889 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 44.
The spelling of 1304117011889 in words is "one trillion, three hundred four billion, one hundred seventeen million, eleven thousand, eight hundred eighty-nine".
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