Base | Representation |
---|---|
bin | 10010111110100011100… |
… | …111000111101111010100 |
3 | 11121200011100220202220210 |
4 | 102332203213013233110 |
5 | 132331314212012322 |
6 | 2435034322125420 |
7 | 163135211242164 |
oct | 22764347075724 |
9 | 4550140822823 |
10 | 1304120032212 |
11 | 46308a83a398 |
12 | 1908b71b0870 |
13 | 95c9385461a |
14 | 471968265a4 |
15 | 23dca9aa70c |
hex | 12fa39c7bd4 |
1304120032212 has 12 divisors (see below), whose sum is σ = 3042946741856. Its totient is φ = 434706677400.
The previous prime is 1304120032147. The next prime is 1304120032261. The reversal of 1304120032212 is 2122300214031.
It is a tau number, because it is divible by the number of its divisors (12).
It is a super-3 number, since 3×13041200322123 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54338334664 + ... + 54338334687.
Almost surely, 21304120032212 is an apocalyptic number.
1304120032212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1304120032212 is an abundant number, since it is smaller than the sum of its proper divisors (1738826709644).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1304120032212 is a wasteful number, since it uses less digits than its factorization.
1304120032212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 108676669358 (or 108676669356 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 1304120032212 its reverse (2122300214031), we get a palindrome (3426420246243).
The spelling of 1304120032212 in words is "one trillion, three hundred four billion, one hundred twenty million, thirty-two thousand, two hundred twelve".
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