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130412244402012 = 2231719563103357853
BaseRepresentation
bin11101101001101111110111…
…100000000111111101011100
3122002202021210112120201122110
4131221233313200013331130
5114043133234031331022
61141210320310114020
736316654663254516
oct3551576740077534
9562667715521573
10130412244402012
113860a582141031
121276292494b910
13579ca8b88a701
14242bdb45dcbb6
1510124c5ddd00c
hex769bf7807f5c

130412244402012 has 192 divisors, whose sum is σ = 340089768184320. Its totient is φ = 38653325991936.

The previous prime is 130412244401983. The next prime is 130412244402023. The reversal of 130412244402012 is 210204442214031.

It is a super-2 number, since 2×1304122444020122 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2254171278 + ... + 2254229130.

It is an arithmetic number, because the mean of its divisors is an integer number (1771300875960).

Almost surely, 2130412244402012 is an apocalyptic number.

130412244402012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130412244402012, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (170044884092160).

130412244402012 is an abundant number, since it is smaller than the sum of its proper divisors (209677523782308).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130412244402012 is a wasteful number, since it uses less digits than its factorization.

130412244402012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59492 (or 59490 counting only the distinct ones).

The product of its (nonzero) digits is 12288, while the sum is 30.

Adding to 130412244402012 its reverse (210204442214031), we get a palindrome (340616686616043).

The spelling of 130412244402012 in words is "one hundred thirty trillion, four hundred twelve billion, two hundred forty-four million, four hundred two thousand, twelve".