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13041401411393 is a prime number
BaseRepresentation
bin1011110111000111000000…
…0110010011011101000001
31201011202010200120010210122
42331301300012103131001
53202132242230131033
643423045340310025
72514132040653605
oct275616006233501
951152120503718
1013041401411393
114178911120973
121567616b42315
13737a50191994
143312c8791505
151793841e1a98
hexbdc70193741

13041401411393 has 2 divisors, whose sum is σ = 13041401411394. Its totient is φ = 13041401411392.

The previous prime is 13041401411383. The next prime is 13041401411413. The reversal of 13041401411393 is 39311410414031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6723477863089 + 6317923548304 = 2592967^2 + 2513548^2 .

It is a cyclic number.

It is not a de Polignac number, because 13041401411393 - 232 = 13037106444097 is a prime.

It is not a weakly prime, because it can be changed into another prime (13041401411383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520700705696 + 6520700705697.

It is an arithmetic number, because the mean of its divisors is an integer number (6520700705697).

Almost surely, 213041401411393 is an apocalyptic number.

It is an amenable number.

13041401411393 is a deficient number, since it is larger than the sum of its proper divisors (1).

13041401411393 is an equidigital number, since it uses as much as digits as its factorization.

13041401411393 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 13041401411393 in words is "thirteen trillion, forty-one billion, four hundred one million, four hundred eleven thousand, three hundred ninety-three".