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13041401411413 is a prime number
BaseRepresentation
bin1011110111000111000000…
…0110010011011101010101
31201011202010200120010211101
42331301300012103131111
53202132242230131123
643423045340310101
72514132040653634
oct275616006233525
951152120503741
1013041401411413
114178911120991
121567616b42331
13737a501919ab
143312c879151b
151793841e1aad
hexbdc70193755

13041401411413 has 2 divisors, whose sum is σ = 13041401411414. Its totient is φ = 13041401411412.

The previous prime is 13041401411393. The next prime is 13041401411453. The reversal of 13041401411413 is 31411410414031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11286791214724 + 1754610196689 = 3359582^2 + 1324617^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13041401411413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13041401411453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520700705706 + 6520700705707.

It is an arithmetic number, because the mean of its divisors is an integer number (6520700705707).

Almost surely, 213041401411413 is an apocalyptic number.

It is an amenable number.

13041401411413 is a deficient number, since it is larger than the sum of its proper divisors (1).

13041401411413 is an equidigital number, since it uses as much as digits as its factorization.

13041401411413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 13041401411413 its reverse (31411410414031), we get a palindrome (44452811825444).

The spelling of 13041401411413 in words is "thirteen trillion, forty-one billion, four hundred one million, four hundred eleven thousand, four hundred thirteen".