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130414251043 is a prime number
BaseRepresentation
bin111100101110101001…
…0111000110000100011
3110110121210102101020001
41321131102320300203
54114042022013133
6135524514000431
712264533562226
oct1713522706043
9413553371201
10130414251043
115034349906a
1221337576117
13c3b49658ab
1464524dd5bd
1535d43de87d
hex1e5d4b8c23

130414251043 has 2 divisors, whose sum is σ = 130414251044. Its totient is φ = 130414251042.

The previous prime is 130414251041. The next prime is 130414251059. The reversal of 130414251043 is 340152414031.

It is a weak prime.

It is an emirp because it is prime and its reverse (340152414031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130414251043 - 21 = 130414251041 is a prime.

Together with 130414251041, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (130414251041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65207125521 + 65207125522.

It is an arithmetic number, because the mean of its divisors is an integer number (65207125522).

Almost surely, 2130414251043 is an apocalyptic number.

130414251043 is a deficient number, since it is larger than the sum of its proper divisors (1).

130414251043 is an equidigital number, since it uses as much as digits as its factorization.

130414251043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 130414251043 its reverse (340152414031), we get a palindrome (470566665074).

The spelling of 130414251043 in words is "one hundred thirty billion, four hundred fourteen million, two hundred fifty-one thousand, forty-three".