Base | Representation |
---|---|
bin | 1011110111001001011001… |
… | …0101110110011101000101 |
3 | 1201011210210101212021220001 |
4 | 2331302112111312131011 |
5 | 3202140101003134000 |
6 | 43423233140241301 |
7 | 2514153661364116 |
oct | 275622625663505 |
9 | 51153711767801 |
10 | 13042043021125 |
11 | 4179110309848 |
12 | 15677759a0231 |
13 | 737b23098a01 |
14 | 331349a8a20d |
15 | 1793c06cd46a |
hex | bdc96576745 |
13042043021125 has 16 divisors (see below), whose sum is σ = 16288104268800. Its totient is φ = 10426176354000.
The previous prime is 13042043021099. The next prime is 13042043021141. The reversal of 13042043021125 is 52112034024031.
It is not a de Polignac number, because 13042043021125 - 215 = 13042042988357 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13042043021093 and 13042043021102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37114741 + ... + 37464490.
It is an arithmetic number, because the mean of its divisors is an integer number (1018006516800).
Almost surely, 213042043021125 is an apocalyptic number.
It is an amenable number.
13042043021125 is a deficient number, since it is larger than the sum of its proper divisors (3246061247675).
13042043021125 is an equidigital number, since it uses as much as digits as its factorization.
13042043021125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74580645 (or 74580635 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 13042043021125 its reverse (52112034024031), we get a palindrome (65154077045156).
The spelling of 13042043021125 in words is "thirteen trillion, forty-two billion, forty-three million, twenty-one thousand, one hundred twenty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •