Base | Representation |
---|---|
bin | 10010111110101001001… |
… | …010111111000111000010 |
3 | 11121200101212110021212212 |
4 | 102332221022333013002 |
5 | 132332012102221010 |
6 | 2435051453422122 |
7 | 163140423210500 |
oct | 22765112770702 |
9 | 4550355407785 |
10 | 1304213320130 |
11 | 463128466a46 |
12 | 19092249a942 |
13 | 95ca9c87c86 |
14 | 471a4d8b670 |
15 | 23dd3c86505 |
hex | 12fa92bf1c2 |
1304213320130 has 24 divisors (see below), whose sum is σ = 2730862993788. Its totient is φ = 447158852448.
The previous prime is 1304213320121. The next prime is 1304213320153. The reversal of 1304213320130 is 310233124031.
It can be written as a sum of positive squares in 2 ways, for example, as 1239407944369 + 64805375761 = 1113287^2 + 254569^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1304213320096 and 1304213320105.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1330829429 + ... + 1330830408.
Almost surely, 21304213320130 is an apocalyptic number.
1304213320130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1304213320130 is an abundant number, since it is smaller than the sum of its proper divisors (1426649673658).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1304213320130 is a wasteful number, since it uses less digits than its factorization.
1304213320130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2661659858 (or 2661659851 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 1304213320130 its reverse (310233124031), we get a palindrome (1614446444161).
The spelling of 1304213320130 in words is "one trillion, three hundred four billion, two hundred thirteen million, three hundred twenty thousand, one hundred thirty".
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