Base | Representation |
---|---|
bin | 1011110111001010000001… |
… | …0110101011111101011011 |
3 | 1201011211020002222010122201 |
4 | 2331302200112223331123 |
5 | 3202140422004344233 |
6 | 43423301541031031 |
7 | 2514161101315534 |
oct | 275624026537533 |
9 | 51154202863581 |
10 | 13042211012443 |
11 | 417919711a148 |
12 | 15678020b5477 |
13 | 737b4bb26962 |
14 | 3313640d968b |
15 | 1793d031377d |
hex | bdca05abf5b |
13042211012443 has 2 divisors, whose sum is σ = 13042211012444. Its totient is φ = 13042211012442.
The previous prime is 13042211012321. The next prime is 13042211012489. The reversal of 13042211012443 is 34421011224031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13042211012443 - 29 = 13042211011931 is a prime.
It is not a weakly prime, because it can be changed into another prime (13042211015443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521105506221 + 6521105506222.
It is an arithmetic number, because the mean of its divisors is an integer number (6521105506222).
Almost surely, 213042211012443 is an apocalyptic number.
13042211012443 is a deficient number, since it is larger than the sum of its proper divisors (1).
13042211012443 is an equidigital number, since it uses as much as digits as its factorization.
13042211012443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 13042211012443 its reverse (34421011224031), we get a palindrome (47463222236474).
The spelling of 13042211012443 in words is "thirteen trillion, forty-two billion, two hundred eleven million, twelve thousand, four hundred forty-three".
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