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1304221131313 is a prime number
BaseRepresentation
bin10010111110101001101…
…000110010001000110001
311121200102102011010210221
4102332221220302020301
5132332021102200223
62435052333053041
7163140546462562
oct22765150621061
94550372133727
101304221131313
11463131911671
12190925027181
1395cab791489
14471a6022169
1523dd47cab5d
hex12fa9a32231

1304221131313 has 2 divisors, whose sum is σ = 1304221131314. Its totient is φ = 1304221131312.

The previous prime is 1304221131289. The next prime is 1304221131347. The reversal of 1304221131313 is 3131311224031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1304111468529 + 109662784 = 1141977^2 + 10472^2 .

It is an emirp because it is prime and its reverse (3131311224031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1304221131313 - 221 = 1304219034161 is a prime.

It is not a weakly prime, because it can be changed into another prime (1304221131373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652110565656 + 652110565657.

It is an arithmetic number, because the mean of its divisors is an integer number (652110565657).

Almost surely, 21304221131313 is an apocalyptic number.

It is an amenable number.

1304221131313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304221131313 is an equidigital number, since it uses as much as digits as its factorization.

1304221131313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1304221131313 its reverse (3131311224031), we get a palindrome (4435532355344).

The spelling of 1304221131313 in words is "one trillion, three hundred four billion, two hundred twenty-one million, one hundred thirty-one thousand, three hundred thirteen".