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1304241123181 is a prime number
BaseRepresentation
bin10010111110101010110…
…101000010111101101101
311121200110210202211111111
4102332222311002331231
5132332041211420211
62435054325352021
7163141211426113
oct22765265027555
94550423684444
101304241123181
11463142126877
1219092b868611
1395cb2970c99
14471a8947ab3
1523dd6429421
hex12faad42f6d

1304241123181 has 2 divisors, whose sum is σ = 1304241123182. Its totient is φ = 1304241123180.

The previous prime is 1304241123121. The next prime is 1304241123209. The reversal of 1304241123181 is 1813211424031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 896515454025 + 407725669156 = 946845^2 + 638534^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304241123181 - 29 = 1304241122669 is a prime.

It is a super-2 number, since 2×13042411231812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1304241123121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652120561590 + 652120561591.

It is an arithmetic number, because the mean of its divisors is an integer number (652120561591).

Almost surely, 21304241123181 is an apocalyptic number.

It is an amenable number.

1304241123181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304241123181 is an equidigital number, since it uses as much as digits as its factorization.

1304241123181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 31.

The spelling of 1304241123181 in words is "one trillion, three hundred four billion, two hundred forty-one million, one hundred twenty-three thousand, one hundred eighty-one".