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130430014281341 is a prime number
BaseRepresentation
bin11101101010000000011010…
…101010110101011001111101
3122002210222122221202010110022
4131222000122222311121331
5114043431132124000331
61141222415452221525
736321154225612055
oct3552003252653175
9562728587663408
10130430014281341
1138617070838415
1212766263a6a8a5
1357a1661218ac8
14242cbbc646565
151012bb5e8c67b
hex76a01aab567d

130430014281341 has 2 divisors, whose sum is σ = 130430014281342. Its totient is φ = 130430014281340.

The previous prime is 130430014281299. The next prime is 130430014281367. The reversal of 130430014281341 is 143182410034031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127739069313241 + 2690944968100 = 11302171^2 + 1640410^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130430014281341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130430014287341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65215007140670 + 65215007140671.

It is an arithmetic number, because the mean of its divisors is an integer number (65215007140671).

Almost surely, 2130430014281341 is an apocalyptic number.

It is an amenable number.

130430014281341 is a deficient number, since it is larger than the sum of its proper divisors (1).

130430014281341 is an equidigital number, since it uses as much as digits as its factorization.

130430014281341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 35.

The spelling of 130430014281341 in words is "one hundred thirty trillion, four hundred thirty billion, fourteen million, two hundred eighty-one thousand, three hundred forty-one".