Base | Representation |
---|---|
bin | 11101101010000000100110… |
… | …011001010110010111010111 |
3 | 122002211000011122221201010011 |
4 | 131222000212121112113113 |
5 | 114043432033010234333 |
6 | 1141222451201141051 |
7 | 36321162135112606 |
oct | 3552004631262727 |
9 | 562730148851104 |
10 | 130430211024343 |
11 | 386171618a633a |
12 | 127662b992a787 |
13 | 57a1692c02799 |
14 | 242cbda81ba3d |
15 | 1012bc83a19cd |
hex | 76a0266565d7 |
130430211024343 has 2 divisors, whose sum is σ = 130430211024344. Its totient is φ = 130430211024342.
The previous prime is 130430211024319. The next prime is 130430211024391. The reversal of 130430211024343 is 343420112034031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130430211024343 - 221 = 130430208927191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130430211024143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65215105512171 + 65215105512172.
It is an arithmetic number, because the mean of its divisors is an integer number (65215105512172).
Almost surely, 2130430211024343 is an apocalyptic number.
130430211024343 is a deficient number, since it is larger than the sum of its proper divisors (1).
130430211024343 is an equidigital number, since it uses as much as digits as its factorization.
130430211024343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 130430211024343 its reverse (343420112034031), we get a palindrome (473850323058374).
The spelling of 130430211024343 in words is "one hundred thirty trillion, four hundred thirty billion, two hundred eleven million, twenty-four thousand, three hundred forty-three".
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