Base | Representation |
---|---|
bin | 11101101010000000110001… |
… | …110110100010110111101111 |
3 | 122002211000200001121121202111 |
4 | 131222000301312202313233 |
5 | 114043432431211231434 |
6 | 1141222522224504451 |
7 | 36321166660603552 |
oct | 3552006166426757 |
9 | 562730601547674 |
10 | 130430403227119 |
11 | 38617250343106 |
12 | 1276635217b127 |
13 | 57a16c3989a38 |
14 | 242cc18170699 |
15 | 1012bda1ba964 |
hex | 76a031da2def |
130430403227119 has 2 divisors, whose sum is σ = 130430403227120. Its totient is φ = 130430403227118.
The previous prime is 130430403227107. The next prime is 130430403227143. The reversal of 130430403227119 is 911722304034031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130430403227119 - 221 = 130430401129967 is a prime.
It is a super-2 number, since 2×1304304032271192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130430403227219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65215201613559 + 65215201613560.
It is an arithmetic number, because the mean of its divisors is an integer number (65215201613560).
Almost surely, 2130430403227119 is an apocalyptic number.
130430403227119 is a deficient number, since it is larger than the sum of its proper divisors (1).
130430403227119 is an equidigital number, since it uses as much as digits as its factorization.
130430403227119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108864, while the sum is 40.
The spelling of 130430403227119 in words is "one hundred thirty trillion, four hundred thirty billion, four hundred three million, two hundred twenty-seven thousand, one hundred nineteen".
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