Base | Representation |
---|---|
bin | 11000010010110110… |
… | …10000111110011101 |
3 | 1020122222210022002002 |
4 | 30021123100332131 |
5 | 203203004404003 |
6 | 5554125412045 |
7 | 641135022041 |
oct | 141133207635 |
9 | 36588708062 |
10 | 13043044253 |
11 | 5593505218 |
12 | 264010a025 |
13 | 12cb293085 |
14 | 8ba372021 |
15 | 515105a88 |
hex | 3096d0f9d |
13043044253 has 4 divisors (see below), whose sum is σ = 13463787648. Its totient is φ = 12622300860.
The previous prime is 13043044241. The next prime is 13043044291. The reversal of 13043044253 is 35244034031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13043044253 - 28 = 13043043997 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13043044153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 210371651 + ... + 210371712.
It is an arithmetic number, because the mean of its divisors is an integer number (3365946912).
Almost surely, 213043044253 is an apocalyptic number.
It is an amenable number.
13043044253 is a deficient number, since it is larger than the sum of its proper divisors (420743395).
13043044253 is an equidigital number, since it uses as much as digits as its factorization.
13043044253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 420743394.
The product of its (nonzero) digits is 17280, while the sum is 29.
Adding to 13043044253 its reverse (35244034031), we get a palindrome (48287078284).
The spelling of 13043044253 in words is "thirteen billion, forty-three million, forty-four thousand, two hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •