13043300342441 has 2 divisors, whose sum is σ = 13043300342442. Its totient is φ = 13043300342440.

The previous prime is 13043300342437. The next prime is 13043300342587. The reversal of 13043300342441 is 14424300334031.

13043300342441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13004137515625 + 39162826816 = 3606125^2 + 197896^2 .

It is a cyclic number.

It is not a de Polignac number, because 13043300342441 - 2² = 13043300342437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13043300342398 and 13043300342407.

It is not a weakly prime, because it can be changed into another prime (13043300342041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521650171220 + 6521650171221.

It is an arithmetic number, because the mean of its divisors is an integer number (6521650171221).

Almost surely, 2^{13043300342441} is an apocalyptic number.

It is an amenable number.

13043300342441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13043300342441 is an equidigital number, since it uses as much as digits as its factorization.

13043300342441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 13043300342441 its reverse (14424300334031), we get a palindrome (27467600676472).

The spelling of 13043300342441 in words is "thirteen trillion, forty-three billion, three hundred million, three hundred forty-two thousand, four hundred forty-one".