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130433132222117 is a prime number
BaseRepresentation
bin11101101010000011010100…
…100000110101011010100101
3122002211021201020200221010022
4131222003110200311122211
5114044004023322101432
61141224053112404525
736321324415641314
oct3552032440653245
9562737636627108
10130433132222117
113861842083347a
12127669940a6745
1357a1a3a185b8a
14242cdd679027b
151012ce9a7bb12
hex76a0d48356a5

130433132222117 has 2 divisors, whose sum is σ = 130433132222118. Its totient is φ = 130433132222116.

The previous prime is 130433132222093. The next prime is 130433132222149. The reversal of 130433132222117 is 711222231334031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 73028885941636 + 57404246280481 = 8545694^2 + 7576559^2 .

It is a cyclic number.

It is not a de Polignac number, because 130433132222117 - 26 = 130433132222053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130433132222317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65216566111058 + 65216566111059.

It is an arithmetic number, because the mean of its divisors is an integer number (65216566111059).

Almost surely, 2130433132222117 is an apocalyptic number.

It is an amenable number.

130433132222117 is a deficient number, since it is larger than the sum of its proper divisors (1).

130433132222117 is an equidigital number, since it uses as much as digits as its factorization.

130433132222117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36288, while the sum is 35.

Adding to 130433132222117 its reverse (711222231334031), we get a palindrome (841655363556148).

The spelling of 130433132222117 in words is "one hundred thirty trillion, four hundred thirty-three billion, one hundred thirty-two million, two hundred twenty-two thousand, one hundred seventeen".