Base | Representation |
---|---|
bin | 11101101010000011010100… |
… | …100000110101011010100101 |
3 | 122002211021201020200221010022 |
4 | 131222003110200311122211 |
5 | 114044004023322101432 |
6 | 1141224053112404525 |
7 | 36321324415641314 |
oct | 3552032440653245 |
9 | 562737636627108 |
10 | 130433132222117 |
11 | 3861842083347a |
12 | 127669940a6745 |
13 | 57a1a3a185b8a |
14 | 242cdd679027b |
15 | 1012ce9a7bb12 |
hex | 76a0d48356a5 |
130433132222117 has 2 divisors, whose sum is σ = 130433132222118. Its totient is φ = 130433132222116.
The previous prime is 130433132222093. The next prime is 130433132222149. The reversal of 130433132222117 is 711222231334031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 73028885941636 + 57404246280481 = 8545694^2 + 7576559^2 .
It is a cyclic number.
It is not a de Polignac number, because 130433132222117 - 26 = 130433132222053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130433132222317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65216566111058 + 65216566111059.
It is an arithmetic number, because the mean of its divisors is an integer number (65216566111059).
Almost surely, 2130433132222117 is an apocalyptic number.
It is an amenable number.
130433132222117 is a deficient number, since it is larger than the sum of its proper divisors (1).
130433132222117 is an equidigital number, since it uses as much as digits as its factorization.
130433132222117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36288, while the sum is 35.
Adding to 130433132222117 its reverse (711222231334031), we get a palindrome (841655363556148).
The spelling of 130433132222117 in words is "one hundred thirty trillion, four hundred thirty-three billion, one hundred thirty-two million, two hundred twenty-two thousand, one hundred seventeen".
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