130433141234129 has 2 divisors, whose sum is σ = 130433141234130. Its totient is φ = 130433141234128.

The previous prime is 130433141234089. The next prime is 130433141234131. The reversal of 130433141234129 is 921432141334031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70552272211600 + 59880869022529 = 8399540^2 + 7738273^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130433141234129 is a prime.

Together with 130433141234131, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130433141234629) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65216570617064 + 65216570617065.

It is an arithmetic number, because the mean of its divisors is an integer number (65216570617065).

Almost surely, 2^{130433141234129} is an apocalyptic number.

It is an amenable number.

130433141234129 is a deficient number, since it is larger than the sum of its proper divisors (1).

130433141234129 is an equidigital number, since it uses as much as digits as its factorization.

130433141234129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 186624, while the sum is 41.

The spelling of 130433141234129 in words is "one hundred thirty trillion, four hundred thirty-three billion, one hundred forty-one million, two hundred thirty-four thousand, one hundred twenty-nine".