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130433231410 = 2513043323141
BaseRepresentation
bin111100101111001101…
…1010010101000110010
3110110200010010200101121
41321132123102220302
54114111401401120
6135530432452454
712265154113456
oct1713633225062
9413603120347
10130433231410
1150353182319
12213419aa12a
13c3b887cb91
146454c40666
1535d5ddd5aa
hex1e5e6d2a32

130433231410 has 8 divisors (see below), whose sum is σ = 234779816556. Its totient is φ = 52173292560.

The previous prime is 130433231389. The next prime is 130433231413. The reversal of 130433231410 is 14132334031.

It can be written as a sum of positive squares in 2 ways, for example, as 127222762489 + 3210468921 = 356683^2 + 56661^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1304332314102 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (130433231413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6521661561 + ... + 6521661580.

Almost surely, 2130433231410 is an apocalyptic number.

130433231410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

130433231410 is a deficient number, since it is larger than the sum of its proper divisors (104346585146).

130433231410 is a wasteful number, since it uses less digits than its factorization.

130433231410 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13043323148.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 130433231410 its reverse (14132334031), we get a palindrome (144565565441).

The spelling of 130433231410 in words is "one hundred thirty billion, four hundred thirty-three million, two hundred thirty-one thousand, four hundred ten".

Divisors: 1 2 5 10 13043323141 26086646282 65216615705 130433231410