1304341331 has 2 divisors, whose sum is σ = 1304341332. Its totient is φ = 1304341330.

The previous prime is 1304341307. The next prime is 1304341333. The reversal of 1304341331 is 1331434031.

It is a strong prime.

It is an emirp because it is prime and its reverse (1331434031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1304341331 - 2⁶ = 1304341267 is a prime.

It is a super-2 number, since 2×1304341331² = 3402612615509703122, which contains 22 as substring.

Together with 1304341333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1304341297 and 1304341306.

It is not a weakly prime, because it can be changed into another prime (1304341333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652170665 + 652170666.

It is an arithmetic number, because the mean of its divisors is an integer number (652170666).

Almost surely, 2^1304341331 is an apocalyptic number.

1304341331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304341331 is an equidigital number, since it uses as much as digits as its factorization.

1304341331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

The square root of 1304341331 is about 36115.6660052116. Note that the first 3 decimals coincide. The cubic root of 1304341331 is about 1092.6064300484.

Adding to 1304341331 its reverse (1331434031), we get a palindrome (2635775362).

The spelling of 1304341331 in words is "one billion, three hundred four million, three hundred forty-one thousand, three hundred thirty-one".