Search a number
-
+
130434232132051 is a prime number
BaseRepresentation
bin11101101010000100010110…
…000100101010000111010011
3122002211101112220101010220021
4131222010112010222013103
5114044013301411211201
61141224354203324311
736321363603010651
oct3552042604520723
9562741486333807
10130434232132051
1138618935697051
1212767040520697
1357a1b84004863
14242d09c8a7dd1
151012d613e5ea1
hex76a11612a1d3

130434232132051 has 2 divisors, whose sum is σ = 130434232132052. Its totient is φ = 130434232132050.

The previous prime is 130434232131991. The next prime is 130434232132109. The reversal of 130434232132051 is 150231232434031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130434232132051 - 211 = 130434232130003 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130434232131998 and 130434232132016.

It is not a weakly prime, because it can be changed into another prime (130434232132151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65217116066025 + 65217116066026.

It is an arithmetic number, because the mean of its divisors is an integer number (65217116066026).

Almost surely, 2130434232132051 is an apocalyptic number.

130434232132051 is a deficient number, since it is larger than the sum of its proper divisors (1).

130434232132051 is an equidigital number, since it uses as much as digits as its factorization.

130434232132051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 34.

Adding to 130434232132051 its reverse (150231232434031), we get a palindrome (280665464566082).

The spelling of 130434232132051 in words is "one hundred thirty trillion, four hundred thirty-four billion, two hundred thirty-two million, one hundred thirty-two thousand, fifty-one".