Base | Representation |
---|---|
bin | 11101101010000100010110… |
… | …000100101010000111010011 |
3 | 122002211101112220101010220021 |
4 | 131222010112010222013103 |
5 | 114044013301411211201 |
6 | 1141224354203324311 |
7 | 36321363603010651 |
oct | 3552042604520723 |
9 | 562741486333807 |
10 | 130434232132051 |
11 | 38618935697051 |
12 | 12767040520697 |
13 | 57a1b84004863 |
14 | 242d09c8a7dd1 |
15 | 1012d613e5ea1 |
hex | 76a11612a1d3 |
130434232132051 has 2 divisors, whose sum is σ = 130434232132052. Its totient is φ = 130434232132050.
The previous prime is 130434232131991. The next prime is 130434232132109. The reversal of 130434232132051 is 150231232434031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130434232132051 - 211 = 130434232130003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130434232131998 and 130434232132016.
It is not a weakly prime, because it can be changed into another prime (130434232132151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65217116066025 + 65217116066026.
It is an arithmetic number, because the mean of its divisors is an integer number (65217116066026).
Almost surely, 2130434232132051 is an apocalyptic number.
130434232132051 is a deficient number, since it is larger than the sum of its proper divisors (1).
130434232132051 is an equidigital number, since it uses as much as digits as its factorization.
130434232132051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 130434232132051 its reverse (150231232434031), we get a palindrome (280665464566082).
The spelling of 130434232132051 in words is "one hundred thirty trillion, four hundred thirty-four billion, two hundred thirty-two million, one hundred thirty-two thousand, fifty-one".
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