Base | Representation |
---|---|
bin | 11000010010111001… |
… | …01111011111101000 |
3 | 1020200000111222010212 |
4 | 30021130233133220 |
5 | 203203104301100 |
6 | 5554142000252 |
7 | 641141223536 |
oct | 141134573750 |
9 | 36600458125 |
10 | 13043431400 |
11 | 559374a07a |
12 | 2640276088 |
13 | 12cb39a35c |
14 | 8ba433156 |
15 | 515180635 |
hex | 30972f7e8 |
13043431400 has 48 divisors (see below), whose sum is σ = 30435587340. Its totient is φ = 5198515200.
The previous prime is 13043431369. The next prime is 13043431463. The reversal of 13043431400 is 413434031.
It can be written as a sum of positive squares in 6 ways, for example, as 5551144036 + 7492287364 = 74506^2 + 86558^2 .
It is a super-2 number, since 2×130434314002 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 62321 + ... + 173120.
Almost surely, 213043431400 is an apocalyptic number.
13043431400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13043431400 is an abundant number, since it is smaller than the sum of its proper divisors (17392155940).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13043431400 is a wasteful number, since it uses less digits than its factorization.
13043431400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 235734 (or 235725 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 13043431400 its reverse (413434031), we get a palindrome (13456865431).
The spelling of 13043431400 in words is "thirteen billion, forty-three million, four hundred thirty-one thousand, four hundred".
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