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130434341144117 is a prime number
BaseRepresentation
bin11101101010000100011100…
…100100100000011000110101
3122002211101211111111112100012
4131222010130210200120311
5114044014012313102432
61141224413100030005
736321366365416253
oct3552043444403065
9562741744445305
10130434341144117
113861899118346a
1212767070b32305
1357a1ba078233a
14242d0ad1635d3
151012d6ac7acb2
hex76a11c920635

130434341144117 has 2 divisors, whose sum is σ = 130434341144118. Its totient is φ = 130434341144116.

The previous prime is 130434341144021. The next prime is 130434341144147. The reversal of 130434341144117 is 711441143434031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129508360270276 + 925980873841 = 11380174^2 + 962279^2 .

It is a cyclic number.

It is not a de Polignac number, because 130434341144117 - 214 = 130434341127733 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130434341144147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65217170572058 + 65217170572059.

It is an arithmetic number, because the mean of its divisors is an integer number (65217170572059).

Almost surely, 2130434341144117 is an apocalyptic number.

It is an amenable number.

130434341144117 is a deficient number, since it is larger than the sum of its proper divisors (1).

130434341144117 is an equidigital number, since it uses as much as digits as its factorization.

130434341144117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 193536, while the sum is 41.

Adding to 130434341144117 its reverse (711441143434031), we get a palindrome (841875484578148).

The spelling of 130434341144117 in words is "one hundred thirty trillion, four hundred thirty-four billion, three hundred forty-one million, one hundred forty-four thousand, one hundred seventeen".