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130439299 is a prime number
BaseRepresentation
bin1111100011001…
…01100010000011
3100002110000002011
413301211202003
5231343024144
620535433351
73142500334
oct761454203
9302400064
10130439299
11676a1a81
1237825857
1321040723
141347628b
15b6b8a34
hex7c65883

130439299 has 2 divisors, whose sum is σ = 130439300. Its totient is φ = 130439298.

The previous prime is 130439297. The next prime is 130439311. The reversal of 130439299 is 992934031.

It is a weak prime.

It is an emirp because it is prime and its reverse (992934031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130439299 - 21 = 130439297 is a prime.

It is a super-2 number, since 2×1304392992 = 34028821447222802, which contains 22 as substring.

Together with 130439297, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130439291) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65219649 + 65219650.

It is an arithmetic number, because the mean of its divisors is an integer number (65219650).

Almost surely, 2130439299 is an apocalyptic number.

130439299 is a deficient number, since it is larger than the sum of its proper divisors (1).

130439299 is an equidigital number, since it uses as much as digits as its factorization.

130439299 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 52488, while the sum is 40.

The square root of 130439299 is about 11421.0025391819. The cubic root of 130439299 is about 507.1496756416.

The spelling of 130439299 in words is "one hundred thirty million, four hundred thirty-nine thousand, two hundred ninety-nine".