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13044000000000 = 2113591087
BaseRepresentation
bin1011110111010000101011…
…1111001000100000000000
31201011222211210021010020010
42331310022333020200000
53202203103000000000
643424155245144520
72514253323415644
oct275641277104000
951158753233203
1013044000000000
114179a24a41a62
12156802125b140
1373807565c388
14331493946c24
151794873e3d50
hexbdd0afc8800

13044000000000 has 480 divisors, whose sum is σ = 43509370544640. Its totient is φ = 3475200000000.

The previous prime is 13043999999969. The next prime is 13044000000049. The reversal of 13044000000000 is 44031.

It is a tau number, because it is divible by the number of its divisors (480).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 11999999457 + ... + 12000000543.

It is an arithmetic number, because the mean of its divisors is an integer number (90644521968).

Almost surely, 213044000000000 is an apocalyptic number.

13044000000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13044000000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21754685272320).

13044000000000 is an abundant number, since it is smaller than the sum of its proper divisors (30465370544640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13044000000000 is an frugal number, since it uses more digits than its factorization.

13044000000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1157 (or 1097 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 12.

Adding to 13044000000000 its reverse (44031), we get a palindrome (13044000044031).

The spelling of 13044000000000 in words is "thirteen trillion, forty-four billion", and thus it is an aban number.