Base | Representation |
---|---|
bin | 1011110111010000101011… |
… | …1111001001100010000111 |
3 | 1201011222211210021100000211 |
4 | 2331310022333021202013 |
5 | 3202203103000113411 |
6 | 43424155245220251 |
7 | 2514253323434200 |
oct | 275641277114207 |
9 | 51158753240024 |
10 | 13044000004231 |
11 | 4179a24a45159 |
12 | 1568021261687 |
13 | 738075661291 |
14 | 3314939485a7 |
15 | 1794873e5221 |
hex | bdd0afc9887 |
13044000004231 has 48 divisors (see below), whose sum is σ = 15760433261664. Its totient is φ = 10758323337216.
The previous prime is 13044000004229. The next prime is 13044000004253. The reversal of 13044000004231 is 13240000044031.
It is not a de Polignac number, because 13044000004231 - 21 = 13044000004229 is a prime.
It is a super-2 number, since 2×130440000042312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13044000004031) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 29309631 + ... + 29751343.
It is an arithmetic number, because the mean of its divisors is an integer number (328342359618).
Almost surely, 213044000004231 is an apocalyptic number.
13044000004231 is a deficient number, since it is larger than the sum of its proper divisors (2716433257433).
13044000004231 is a wasteful number, since it uses less digits than its factorization.
13044000004231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 442000 (or 441993 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 13044000004231 its reverse (13240000044031), we get a palindrome (26284000048262).
The spelling of 13044000004231 in words is "thirteen trillion, forty-four billion, four thousand, two hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •