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13044000120103 = 471991394632751
BaseRepresentation
bin1011110111010000101011…
…1111100101110100100111
31201011222211210111012222101
42331310022333211310213
53202203103012320403
643424155251512531
72514253324426051
oct275641277456447
951158753435871
1013044000120103
114179a25014217
1215680212b8747
137380756a1c44
143314939788d1
1517948741971d
hexbdd0afe5d27

13044000120103 has 8 divisors (see below), whose sum is σ = 13388474419200. Its totient is φ = 12702315087000.

The previous prime is 13044000120059. The next prime is 13044000120199. The reversal of 13044000120103 is 30102100044031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13044000120103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044000120703) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 697307023 + ... + 697325728.

It is an arithmetic number, because the mean of its divisors is an integer number (1673559302400).

Almost surely, 213044000120103 is an apocalyptic number.

13044000120103 is a deficient number, since it is larger than the sum of its proper divisors (344474299097).

13044000120103 is a wasteful number, since it uses less digits than its factorization.

13044000120103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1394632997.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 13044000120103 its reverse (30102100044031), we get a palindrome (43146100164134).

The spelling of 13044000120103 in words is "thirteen trillion, forty-four billion, one hundred twenty thousand, one hundred three".

Divisors: 1 47 199 9353 1394632751 65547739297 277531917449 13044000120103