130440011213000 has 128 divisors (see below), whose sum is σ = 309947533758720. Its totient is φ = 51370340313600.

The previous prime is 130440011212967. The next prime is 130440011213009. The reversal of 130440011213000 is 312110044031.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is not an unprimeable number, because it can be changed into a prime (130440011213009) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 127662149 + ... + 128679851.

It is an arithmetic number, because the mean of its divisors is an integer number (2421465107490).

Almost surely, 2^{130440011213000} is an apocalyptic number.

130440011213000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130440011213000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (154973766879360).

130440011213000 is an abundant number, since it is smaller than the sum of its proper divisors (179507522545720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130440011213000 is a wasteful number, since it uses less digits than its factorization.

130440011213000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1019704 (or 1019690 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 130440011213000 its reverse (312110044031), we get a palindrome (130752121257031).

The spelling of 130440011213000 in words is "one hundred thirty trillion, four hundred forty billion, eleven million, two hundred thirteen thousand".