Base | Representation |
---|---|
bin | 1011110111010000101100… |
… | …0100100101100111111110 |
3 | 1201011222211212221202211121 |
4 | 2331310023010211213332 |
5 | 3202203103331230024 |
6 | 43424155335541154 |
7 | 2514253341523042 |
oct | 275641304454776 |
9 | 51158755852747 |
10 | 13044001430014 |
11 | 4179a25829395 |
12 | 156802182a7ba |
13 | 738075a40239 |
14 | 331493bda022 |
15 | 1794875c78e4 |
hex | bdd0b1259fe |
13044001430014 has 4 divisors (see below), whose sum is σ = 19566002145024. Its totient is φ = 6522000715006.
The previous prime is 13044001429997. The next prime is 13044001430041. The reversal of 13044001430014 is 41003410044031.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3261000357502 + ... + 3261000357505.
It is an arithmetic number, because the mean of its divisors is an integer number (4891500536256).
Almost surely, 213044001430014 is an apocalyptic number.
13044001430014 is a deficient number, since it is larger than the sum of its proper divisors (6522000715010).
13044001430014 is an equidigital number, since it uses as much as digits as its factorization.
13044001430014 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6522000715009.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13044001430014 its reverse (41003410044031), we get a palindrome (54047411474045).
The spelling of 13044001430014 in words is "thirteen trillion, forty-four billion, one million, four hundred thirty thousand, fourteen".
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