Base | Representation |
---|---|
bin | 11101101010001001101111… |
… | …010010111101100000010011 |
3 | 122002211221111112211120220012 |
4 | 131222021233102331200103 |
5 | 114044112132122133021 |
6 | 1141231153023505135 |
7 | 36321660252160415 |
oct | 3552115722754023 |
9 | 562757445746805 |
10 | 130440024021011 |
11 | 38620337aa4a41 |
12 | 127681981581ab |
13 | 57a2597c364a3 |
14 | 242d48bbc29b5 |
15 | 101309eb2135b |
hex | 76a26f4bd813 |
130440024021011 has 2 divisors, whose sum is σ = 130440024021012. Its totient is φ = 130440024021010.
The previous prime is 130440024020963. The next prime is 130440024021023. The reversal of 130440024021011 is 110120420044031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130440024021011 is a prime.
It is not a weakly prime, because it can be changed into another prime (130440024021031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220012010505 + 65220012010506.
It is an arithmetic number, because the mean of its divisors is an integer number (65220012010506).
Almost surely, 2130440024021011 is an apocalyptic number.
130440024021011 is a deficient number, since it is larger than the sum of its proper divisors (1).
130440024021011 is an equidigital number, since it uses as much as digits as its factorization.
130440024021011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 130440024021011 its reverse (110120420044031), we get a palindrome (240560444065042).
The spelling of 130440024021011 in words is "one hundred thirty trillion, four hundred forty billion, twenty-four million, twenty-one thousand, eleven".
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