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130440024021023 is a prime number
BaseRepresentation
bin11101101010001001101111…
…010010111101100000011111
3122002211221111112211120220122
4131222021233102331200133
5114044112132122133043
61141231153023505155
736321660252160433
oct3552115722754037
9562757445746818
10130440024021023
1138620337aa4a52
12127681981581bb
1357a2597c364b2
14242d48bbc29c3
15101309eb21368
hex76a26f4bd81f

130440024021023 has 2 divisors, whose sum is σ = 130440024021024. Its totient is φ = 130440024021022.

The previous prime is 130440024021011. The next prime is 130440024021031. The reversal of 130440024021023 is 320120420044031.

It is a strong prime.

It is an emirp because it is prime and its reverse (320120420044031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130440024021023 - 230 = 130438950279199 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130440024020983 and 130440024021001.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130440024020023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220012010511 + 65220012010512.

It is an arithmetic number, because the mean of its divisors is an integer number (65220012010512).

Almost surely, 2130440024021023 is an apocalyptic number.

130440024021023 is a deficient number, since it is larger than the sum of its proper divisors (1).

130440024021023 is an equidigital number, since it uses as much as digits as its factorization.

130440024021023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 130440024021023 its reverse (320120420044031), we get a palindrome (450560444065054).

The spelling of 130440024021023 in words is "one hundred thirty trillion, four hundred forty billion, twenty-four million, twenty-one thousand, twenty-three".