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130440041100223 = 472775320023409
BaseRepresentation
bin11101101010001001110000…
…010100000111001110111111
3122002211221112201222022011121
4131222021300110013032333
5114044112201010201343
61141231154433531411
736321660550303141
oct3552116024071677
9562757481868147
10130440041100223
11386203466aa898
12127681a1a13b67
1357a259b63632a
14242d49018ac91
1510130a1396aed
hex76a2705073bf

130440041100223 has 4 divisors (see below), whose sum is σ = 133215361123680. Its totient is φ = 127664721076768.

The previous prime is 130440041100217. The next prime is 130440041100233. The reversal of 130440041100223 is 322001140044031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130440041100223 - 241 = 128241017844671 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130440041100203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1387660011658 + ... + 1387660011751.

It is an arithmetic number, because the mean of its divisors is an integer number (33303840280920).

Almost surely, 2130440041100223 is an apocalyptic number.

130440041100223 is a deficient number, since it is larger than the sum of its proper divisors (2775320023457).

130440041100223 is an equidigital number, since it uses as much as digits as its factorization.

130440041100223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2775320023456.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 130440041100223 its reverse (322001140044031), we get a palindrome (452441181144254).

The spelling of 130440041100223 in words is "one hundred thirty trillion, four hundred forty billion, forty-one million, one hundred thousand, two hundred twenty-three".

Divisors: 1 47 2775320023409 130440041100223